# The height of the water column in the glass is 5 cm. What will be the pressure of the liquid

**The height of the water column in the glass is 5 cm. What will be the pressure of the liquid on the bottom of the glass if kerosene is poured to the same level instead of water?**

To solve this problem, you first need to translate the value of the height of the water column in the glass from centimeters to meters.

Since there is 100 cm in 1 meter, we get:

5/100 = 0.05 m.

Determine the water pressure at the bottom of the glass using the following formula:

P = p * g * h,

where:

P is the pressure;

p is the density;

g is the force of gravity;

h is the height of the post.

Substitute the known values into the formula.

P = 1000 * 9.8 * 0.05 = 490 Pa (water pressure).

Since the density of kerosene is 800 kg / m3, the pressure at the bottom of the glass will be equal to:

P = 800 * 9.8 * 0.05 = 392 Pa (kerosene pressure).

Answer:

392 Pa.